Question

Find the capacitance of a series plate of capacitor:

• C1 = 3.4x10^-3F
• C2 = 5.0x10^-13F
• C3 = 4.3x10^-9F
• Vt = 500v

Answer 1

The total capacitance of the series capacitors can be found as follows (see https://www.allaboutcircuits.com/textbook/direct-current/chpt-13/series-and-parallel-capacitors/):

$$C = \dfrac{1}{\dfrac{1}{C1} + \dfrac{1}{C2}+\dfrac{1}{C3}}$$

Substituting the values, obtain:

$$C = \dfrac{1}{\dfrac{1}{3.4\times 10^{-3}} + \dfrac{1}{5\times 10^{-13}}+\dfrac{1}{4.3\times 10^{-9}}} \approx 4.999\times 10^{-13}F$$

Answer. $4.999\times 10^{-13}F$.