Question #181308

Two blocks of weights W1 = W2 = 10KN rest on a rough inclined plane and are connected by a short piece of string as shown. If the coefficient of friction is μ1 = 0.20 and μ2 = 0.30 respectively: Determine a) The inclination of the plane for which sliding will impend.



Expert's answer


Sliding will start when the inclination will exceed some angle θ\theta.

Write forces acting on each block:


1. x:f1+TWsinθ=0,y:Wcosθ=N. 2. x:f2TWsinθ=0,y:Wcosθ=N.1.\space x:f_1+T-W\sin\theta=0,\\ y: W\cos\theta=N.\\\space\\ 2.\space x:f_2-T-W\sin\theta=0,\\ y: W\cos\theta=N.

Since f=μNf=\mu N,


1. μ1Wcosθ+TWsinθ=0,2. μ2WcosθTWsinθ=0,1.\space \mu_1W\cos\theta+T-W\sin\theta=0,\\ 2.\space \mu_2W\cos\theta-T-W\sin\theta=0,\\

add these equations:


cosθW(μ1+μ2)2Wsinθ=0,cosθ(μ1+μ2)=2sinθ, tanθ=μ1+μ22, θ=arctanμ1+μ22=14°.\cos\theta ·W(\mu_1+\mu_2)-2W\sin\theta=0,\\ \cos\theta ·(\mu_1+\mu_2)=2\sin\theta,\\\space\\ \tan\theta=\frac{\mu_1+\mu_2}{2},\\\space\\ \theta=\arctan\frac{\mu_1+\mu_2}{2}=14°.
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