Question #181308

Two blocks of weights W1 = W2 = 10KN rest on a rough inclined plane and are connected by a short piece of string as shown. If the coefficient of friction is μ1 = 0.20 and μ2 = 0.30 respectively: Determine a) The inclination of the plane for which sliding will impend.



1
Expert's answer
2021-04-16T07:24:02-0400


Sliding will start when the inclination will exceed some angle θ\theta.

Write forces acting on each block:


1. x:f1+TWsinθ=0,y:Wcosθ=N. 2. x:f2TWsinθ=0,y:Wcosθ=N.1.\space x:f_1+T-W\sin\theta=0,\\ y: W\cos\theta=N.\\\space\\ 2.\space x:f_2-T-W\sin\theta=0,\\ y: W\cos\theta=N.

Since f=μNf=\mu N,


1. μ1Wcosθ+TWsinθ=0,2. μ2WcosθTWsinθ=0,1.\space \mu_1W\cos\theta+T-W\sin\theta=0,\\ 2.\space \mu_2W\cos\theta-T-W\sin\theta=0,\\

add these equations:


cosθW(μ1+μ2)2Wsinθ=0,cosθ(μ1+μ2)=2sinθ, tanθ=μ1+μ22, θ=arctanμ1+μ22=14°.\cos\theta ·W(\mu_1+\mu_2)-2W\sin\theta=0,\\ \cos\theta ·(\mu_1+\mu_2)=2\sin\theta,\\\space\\ \tan\theta=\frac{\mu_1+\mu_2}{2},\\\space\\ \theta=\arctan\frac{\mu_1+\mu_2}{2}=14°.

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