What is the kinetic energy of automobile with a mass of 1.25 x 10^3 kg traveling at a speed of 10.0m/s
The kinetic energy of the automobile is:
E=mv22=1.25⋅103kg⋅102m2s22=62500J=62.5kJ.E = \frac{m v^2}{2} = \frac{1.25 \cdot 10^3 kg \cdot 10^2 \frac{m^2}{s^2}}{2} = 62500 J = 62.5 kJ.E=2mv2=21.25⋅103kg⋅102s2m2=62500J=62.5kJ.
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