0.5 kg of water at 20 degrees C is added to a container of 1 kg of water at 60 degrees C.
The water is stirred to even out the temperature. What is the final
temperature of the water?
Let "T" be the final temperature of the water, "T_1", "m_1" the temperature and mass of the water that is added, and "T_2, m_2" the temperature and mass of the water in the container.
Equation of energy balance is "c_w m_1 (T-T_1) + c_w m_2 (T - T_2) = 0", from where "T = \\frac{c_w m_1 T_1 + c_w m_2 T_2}{c_w m_1 + c_w m_2} = \\frac{m_1 T_1 + m_2 T_2}{m_1 + m_2} \\approx 46.7 ^{\\circ}C"
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