what is the electric field from an electron 1.0cm away from it?
Electric field of point charge qqq at distance rrr from it is E=kqr2E = \frac{k q}{r^2}E=r2kq, where k≈9⋅109N⋅m2C2k \approx 9 \cdot 10^9 \frac{N \cdot m^2}{C^2}k≈9⋅109C2N⋅m2is the Coulomb's constant.
Hence, E=ker2=9⋅109N⋅m2C2⋅1.6⋅10−19C(1⋅10−2)2m2≈14.4⋅10−6VmE = \frac{k e}{r^2} = \frac{9 \cdot 10^9 \frac{N \cdot m^2}{C^2} \cdot 1.6 \cdot 10^{-19} C}{(1 \cdot 10^{-2})^2 m^2} \approx 14.4 \cdot 10^{-6} \frac{V}{m}E=r2ke=(1⋅10−2)2m29⋅109C2N⋅m2⋅1.6⋅10−19C≈14.4⋅10−6mV.
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