a stone is thrown straight downward with an initial speed 9.0m/s from a height of 25m.Find the time taken to reach the ground
h=v0t+gt2/2→25=9t+9.81t2/2→h=v_0t+gt^2/2\to25=9t+9.81t^2/2\toh=v0t+gt2/2→25=9t+9.81t2/2→
4.905t2+9t−25=0→t=1.52 (s)4.905t^2+9t-25=0\to t=1.52\ (s)4.905t2+9t−25=0→t=1.52 (s) . Answer
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