Question

You are pushing a box along the ground (no friction) forward (+direction) with a force of 54N. Your classmate is also pushing on the box, but they are pushing to the backward direction (opposite of you) with a force magnitude of 2 N. what is the net force on the box ?

Answer 1

$$F_{net}=F_1-F_2=54\ N-2\ N=52\ N.$$