Question

A projectile is launched from ground level with the initial velocity of 50.0 m/s . The time of the flight is measured to be 6.00 s. How far from the launch point does the projectile land? Neglect the air resistance and g = 10.0 m/s^2

(A) 120 m

(B) 150 m

(C) 240 m

(D) 300 m

Answer 1

From the time of the flight find the angle above the horizontal:

$$\frac t2=\frac{v\sin\theta}{g},\\\space\\ \theta=\arcsin\frac{gt}{2v}.$$

Find how far the projectile landed:

$$R=tv\cos\theta=tv\cos\bigg[\arcsin\frac{gt}{2v}\bigg]=240\text{ m}.$$