Question

Two equal and opposite forces each of magnitude 40N are applied to the rim of a wheel makes 12 revolutions while the torque is kept constant. Calculate the angle of revolution, the torque and the workdone

Answer 1

$$\theta=12(2\pi)=24\pi \ rad\\\tau=2Tr=2(40)(2.5)=200\ Nm\\ W=\tau \theta=(24\pi)(200)=15080\ J$$