2 kg of mass is placed on x axis 2m away from the origin, the particle is released from rest to fall under the effect of gravity. Calculate the angular momentum and torque
At t=0t=0t=0 the angular momentum is L=0L=0L=0.
Torque τ=r⋅F=r⋅mg=2⋅2⋅9.81=39.24 (N⋅m)\tau=r\cdot F=r\cdot mg=2\cdot2\cdot9.81=39.24\ (N\cdot m)τ=r⋅F=r⋅mg=2⋅2⋅9.81=39.24 (N⋅m) .
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