Question #178787

What displacement must be added to a 50cm displacement in the +x-direction to give a resultant displacement of 85cm at 25 degree's



1
Expert's answer
2021-04-08T07:34:31-0400

Let denote the initial displacement with a vector d1\mathbf{d}_1 with the following coordinates:


d1=(50,0)\mathbf{d}_1 = (50, 0)


and the unknown displacement with d2=(x,y)\mathbf{d}_2 = (x,y).

The final displacement is:


d=85(cos25°,sin25°)\mathbf{d} = 85\cdot (\cos25\degree, \sin25\degree)

Then, since


d1+d2=dd2=dd1(x,y)=85(cos25°,sin25°)(50,0)\mathbf{d}_1 + \mathbf{d}_2 = \mathbf{d}\\ \mathbf{d}_2 = \mathbf{d}-\mathbf{d}_1\\ (x, y) = 85\cdot (\cos25\degree, \sin25\degree) - (50, 0)

Comparing coordinatewisely both sides, find:


x=85cos25°5027cmy=85sin25°036cmx = 85\cos25\degree-50\approx 27cm\\ y = 85\sin25\degree-0 \approx 36cm

Answer. (27, 36) cm.


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