Let denote the initial displacement with a vector d1 with the following coordinates:
d1=(50,0)
and the unknown displacement with d2=(x,y).
The final displacement is:
d=85⋅(cos25°,sin25°) Then, since
d1+d2=dd2=d−d1(x,y)=85⋅(cos25°,sin25°)−(50,0) Comparing coordinatewisely both sides, find:
x=85cos25°−50≈27cmy=85sin25°−0≈36cm Answer. (27, 36) cm.
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