F = F 13 − F 23 = k q 1 q 3 / r 13 2 − k q 2 q 3 / r 23 2 = F=F_{13}-F_{23}=k{q_1q_3}/{r_{13}^2}-kq_2q_3/r_{23}^2= F = F 13 − F 23 = k q 1 q 3 / r 13 2 − k q 2 q 3 / r 23 2 =
= 9 ⋅ 1 0 9 ⋅ 50 ⋅ 1 0 − 6 ⋅ 20 ⋅ 1 0 − 6 / 1 0 2 − =9\cdot10^9\cdot50\cdot10^{-6}\cdot20\cdot10^{-6}/10^2- = 9 ⋅ 1 0 9 ⋅ 50 ⋅ 1 0 − 6 ⋅ 20 ⋅ 1 0 − 6 /1 0 2 −
− 9 ⋅ 1 0 − 9 ⋅ 50 ⋅ 1 0 − 6 ⋅ 20 ⋅ 1 0 − 6 / 1 0 2 = 0 -9\cdot10^{-9}\cdot50\cdot 10^{-6}\cdot20\cdot10^{-6}/10^2=0 − 9 ⋅ 1 0 − 9 ⋅ 50 ⋅ 1 0 − 6 ⋅ 20 ⋅ 1 0 − 6 /1 0 2 = 0 . Answer
F = F 13 2 + F 23 2 + 2 F 13 F 23 cos 73.74 ° F=\sqrt{F_{13}^2+F_{23}^2+2F_{13}F_{23}\cos73.74°} F = F 13 2 + F 23 2 + 2 F 13 F 23 cos 73.74°
F 13 = k q 1 q 3 / r 13 2 = F_{13}=k{q_1q_3}/{r_{13}^2}= F 13 = k q 1 q 3 / r 13 2 =
= 9 ⋅ 1 0 9 ⋅ 40 ⋅ 1 0 − 6 ⋅ 50 ⋅ 1 0 − 6 / 5 2 = 0.72 ( N ) =9\cdot10^9\cdot40\cdot10^{-6}\cdot50\cdot10^{-6}/5^2=0.72\ (N) = 9 ⋅ 1 0 9 ⋅ 40 ⋅ 1 0 − 6 ⋅ 50 ⋅ 1 0 − 6 / 5 2 = 0.72 ( N )
F 23 = k q 2 q 3 / r 23 2 = F_{23}=kq_2q_3/r_{23}^2= F 23 = k q 2 q 3 / r 23 2 =
= 9 ⋅ 1 0 9 ⋅ 20 ⋅ 1 0 − 6 ⋅ 50 ⋅ 1 0 − 6 / 5 2 = 0.36 ( N ) =9\cdot10^9\cdot20\cdot10^{-6}\cdot50\cdot10^{-6}/5^2=0.36\ (N) = 9 ⋅ 1 0 9 ⋅ 20 ⋅ 1 0 − 6 ⋅ 50 ⋅ 1 0 − 6 / 5 2 = 0.36 ( N )
F = 0.7 2 2 + 0.3 6 2 + 2 ⋅ 0.72 ⋅ 0.36 ⋅ cos 73.74 ° = F=\sqrt{0.72^2+0.36^2+2\cdot0.72\cdot 0.36\cdot\cos73.74°}= F = 0.7 2 2 + 0.3 6 2 + 2 ⋅ 0.72 ⋅ 0.36 ⋅ cos 73.74° =
= 0.89 ( N ) =0.89\ (N) = 0.89 ( N ) . Answer
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