Answer to Question #178096 in Physics for Afolabi Fola

Question #178096

An engine raises 100 kg of water through a height of 60 m in 20 sec. What is the power of the engine?(Take g = 10 m /s²)


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Expert's answer
2021-04-05T11:08:47-0400
P=Wt=mght,P=\dfrac{W}{t}=\dfrac{mgh}{t},P=100 kg10 ms260 m20 s=3000 W=3 kW.P=\dfrac{100\ kg\cdot10\ \dfrac{m}{s^2}\cdot60\ m}{20\ s}=3000\ W=3\ kW.

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Comments

Gemini
21.09.21, 01:52

Awesome! ❤️

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