Answer to Question #178096 in Physics for Afolabi Fola

Question

An engine raises 100 kg of water through a height of 60 m in 20 sec. What is the power of the engine?(Take g = 10 m /s²)

Answer 1

$$P=\dfrac{W}{t}=\dfrac{mgh}{t},$$ $$P=\dfrac{100\ kg\cdot10\ \dfrac{m}{s^2}\cdot60\ m}{20\ s}=3000\ W=3\ kW.$$