A circular disk with a radius of 15 mm rotates at a constant angular speed of 5 revolutions per second. Determine the acceleration of a point on the circumference of the disk. (solution- ac = 14,789 m / s2)
a=ac=ω2r=(2⋅3.14⋅5)2⋅0.15=14.789 (m/s2)a=a_c=\omega^2r=(2\cdot3.14\cdot5)^2\cdot0.15=14.789\ (m/s^2)a=ac=ω2r=(2⋅3.14⋅5)2⋅0.15=14.789 (m/s2)
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