R = R 0 ( 1 + α t ) R=R_0(1+\alpha t) R = R 0 ( 1 + α t )
(a)
R = ρ l A → A = ρ l R = 1.59 ⋅ 1 0 − 8 ⋅ 1.2 30 = 636 ⋅ 1 0 − 12 ( m 2 ) R=\rho\frac{l}{A} \to A=\rho\frac{l}{R}=1.59\cdot10^{-8}\cdot\frac{1.2}{30}=636\cdot10^{-12}\ (m^2) R = ρ A l → A = ρ R l = 1.59 ⋅ 1 0 − 8 ⋅ 30 1.2 = 636 ⋅ 1 0 − 12 ( m 2 )
A = π r 2 → r = A π = 636 ⋅ 1 0 − 12 3.14 = 1.42 ⋅ 1 0 − 5 ( m ) A=\pi r^2\to \frac{}{}r=\sqrt{\frac{A}{\pi}}=\sqrt{\frac{636\cdot10^{-12}}{3.14}}=1.42\cdot10^{-5}\ (m) A = π r 2 → r = π A = 3.14 636 ⋅ 1 0 − 12 = 1.42 ⋅ 1 0 − 5 ( m ) . Answer
(b)
R = R 0 ( 1 + α t ) → R=R_0(1+\alpha t)\to R = R 0 ( 1 + α t ) →
R = R 0 ( 1 + 0.0038 ⋅ 20 ) R=R_0(1+0.0038\cdot20) R = R 0 ( 1 + 0.0038 ⋅ 20 )
R 10 = R 0 ( 1 + 0.0038 ⋅ 10 ) → R_{10}=R_0(1+0.0038\cdot10)\to R 10 = R 0 ( 1 + 0.0038 ⋅ 10 ) →
R / R 10 = ( 1 + 0.0038 ⋅ 20 ) / ( 1 + 0.0038 ⋅ 10 ) R/R_{10}=(1+0.0038\cdot20)/(1+0.0038\cdot10) R / R 10 = ( 1 + 0.0038 ⋅ 20 ) / ( 1 + 0.0038 ⋅ 10 )
30 / R 10 = 1.0366 → R 10 = 28.94 ( Ω ) 30/R_{10}=1.0366\to R_{10}=28.94\ (\Omega) 30/ R 10 = 1.0366 → R 10 = 28.94 ( Ω ) . Answer
(c)
ρ = ρ 0 ( 1 + α t ) \rho=\rho_0(1+\alpha t) ρ = ρ 0 ( 1 + α t )
1.59 ⋅ 1 0 − 8 = ρ 0 ( 1 + 0.0038 ⋅ 20 ) 1.59\cdot10^{-8}=\rho_0(1+0.0038\cdot20) 1.59 ⋅ 1 0 − 8 = ρ 0 ( 1 + 0.0038 ⋅ 20 )
ρ 25 = ρ 0 ( 1 + 0.0038 ⋅ 25 ) \rho_{25}=\rho_0(1+0.0038\cdot25) ρ 25 = ρ 0 ( 1 + 0.0038 ⋅ 25 )
1.59 ⋅ 1 0 − 8 / ρ 25 = ρ 0 ( 1 + 0.0038 ⋅ 20 ) / ρ 0 ( 1 + 0.0038 ⋅ 25 ) → 1.59\cdot10^{-8}/\rho_{25}=\rho_0(1+0.0038\cdot20)/\rho_0(1+0.0038\cdot25)\to 1.59 ⋅ 1 0 − 8 / ρ 25 = ρ 0 ( 1 + 0.0038 ⋅ 20 ) / ρ 0 ( 1 + 0.0038 ⋅ 25 ) →
1.59 ⋅ 1 0 − 8 / ρ 25 = 0.9826 → ρ 25 = 1.62 ⋅ 1 0 − 8 1.59\cdot10^{-8}/\rho_{25}=0.9826\to \rho_{25}=1.62\cdot10^{-8} 1.59 ⋅ 1 0 − 8 / ρ 25 = 0.9826 → ρ 25 = 1.62 ⋅ 1 0 − 8 . Answer
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