Answer to Question #177195 in Physics for Pushpa

Question #177195

Determine the extension of the spring when it has a spring constant k= 60 N/m with 25 J of potential energy.

Expert's answer

"PE=\\dfrac{1}{2}kx^2,""x=\\sqrt{\\dfrac{2PE}{k}}=\\sqrt{\\dfrac{2\\cdot25\\ J}{60\\ \\dfrac{N}{m}}}=0.91\\ m."

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