A 1000 kg car is travelling on the highway at a constant speed of 110 km/h.
So,
A 1000 kg car is travelling on the highway at a constant speed of 110 km/h. The highway makes a turn that is banked at an angle of 10° and has a radius of 160 m. What is the coefficient of friction between the car tires and the pavement in the curve?
"F_{net}=m\\cdot\\frac{v^2}{r}"
"F_{net}=N\\sin10\u00b0+\\mu N\\cos10\u00b0"
"mg+\\mu N\\sin10\u00b0=N\\cos10\u00b0"
"N\\sin10\u00b0+\\mu N\\cos10\u00b0=m\\cdot\\frac{v^2}{r}"
We have
"\\mu=\\frac{(v^2\/(gr))\\cos10\u00b0-\\sin10\u00b0}{(v^2\/(gr))\\sin10\u00b0+\\cos10\u00b0}=\\frac{(30.6^2\/(9.8\\cdot160)\\cos10\u00b0-\\sin10\u00b0}{(30.6^2\/(9.8\\cdot160)\\sin10\u00b0+\\cos10\u00b0}=0.381" . Answer
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