Question #177042

A 1000 kg car is travelling on the highway at a constant speed of 110 km/h.



1
Expert's answer
2021-03-31T09:32:03-0400

So,


A 1000 kg car is travelling on the highway at a constant speed of 110 km/h. The highway makes a turn that is banked at an angle of 10° and has a radius of 160 m. What is the coefficient of friction between the car tires and the pavement in the curve?



Fnet=mv2rF_{net}=m\cdot\frac{v^2}{r}


Fnet=Nsin10°+μNcos10°F_{net}=N\sin10°+\mu N\cos10°



mg+μNsin10°=Ncos10°mg+\mu N\sin10°=N\cos10°


Nsin10°+μNcos10°=mv2rN\sin10°+\mu N\cos10°=m\cdot\frac{v^2}{r}


We have


μ=(v2/(gr))cos10°sin10°(v2/(gr))sin10°+cos10°=(30.62/(9.8160)cos10°sin10°(30.62/(9.8160)sin10°+cos10°=0.381\mu=\frac{(v^2/(gr))\cos10°-\sin10°}{(v^2/(gr))\sin10°+\cos10°}=\frac{(30.6^2/(9.8\cdot160)\cos10°-\sin10°}{(30.6^2/(9.8\cdot160)\sin10°+\cos10°}=0.381 . Answer







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