Vector A has magnitude 4 units, vector B has magnitude 6 units. The angle between A and B is 60°. Calculate the magnitude of 2A + 3B.
2A=2⋅4=82A=2\cdot4=82A=2⋅4=8
3B=3⋅6=183B=3\cdot6=183B=3⋅6=18
2A+3B=82+182+2⋅8⋅18⋅cos60°=23.0652A+3B=\sqrt{8^2+18^2+2\cdot8\cdot18\cdot\cos60°}=23.0652A+3B=82+182+2⋅8⋅18⋅cos60°=23.065 . Answer
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