Answer to Question #176905 in Physics for Christian

Question

what will be the electric potential if the source charge is placed 2. 08 x 10 - 13 m away from the +5. 02 x 10 - 13C Source charge?

Answer 1

$$V=k\frac{q}{r}\\V=8.99\cdot10^9\frac{5.02\cdot10^{-13}}{2.08\cdot10^{-13}}=2.17\cdot10^{10}V$$