3. The 100g block, which moves at a speed of 4m / s, starts to brake until it stops. The work done in this case is:
A) -800 J
B) 8 J
C) 0.8J
D) -0.8J
W=ΔKE=mv2/2−mv02/2=0−0.1⋅42/2=−0.8 (J)W=\Delta KE=mv^2/2-mv_0^2/2=0-0.1\cdot4^2/2=-0.8\ (J)W=ΔKE=mv2/2−mv02/2=0−0.1⋅42/2=−0.8 (J) . Answer
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments