Answer to Question #176120 in Physics for Agboola

Question #176120

2000 identical drops of density 2.8 have a mass of 4.2*10^-8kg. If 80 of the drops form a thin film where thickness is 9.4Pm on water, calculate the area of the film over water

Expert's answer

"V=N\\frac{m}{\\rho}=Ah\\\\2000\\frac{(4.2\\cdot10^{-8})}{2800}=(9.4\\cdot10^{-12})A\\\\A=3200\\ m^2"

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