Question

A motor capable of producing a constant torque of 100Nm and maximum rotation speed of 150 rad/s is

connected to a flywheel with rotational inertia 0.1 kg-m2

. What angular acceleration will the flywheel

experience as the motor is switched on?

Answer 1

Acording to the main equation of the rotational dynamics, obtain:

$$\tau = I\varepsilon$$

where $\tau = 100N\cdot m$ is the applied torque, $I = 0.1kg\cdot m^2$ is the moment of inertia, and $\varepsilon$ is the angular acceleration. Thus, obtain:

$$\varepsilon = \dfrac{\tau}{I}\\ \varepsilon = \dfrac{100N\cdot m}{0.1kg\cdot m^2} = 1000\space rad/s^2$$

Answer. $1000\space rad/s^2$.