Question

a 2000 lb block lies on a smooth plane at 50 degrees with the horizontal. find the horizontal force needed to hold the block on the inclined plane.

Answer 1

$2000\ (lb)\approx907\ (kg)$

$mg\sin50°=F\cos50°\to F=mg\sin50°/\cos50°=$

$=907\cdot9.81\cdot\sin50°/\cos50°=10604\ (N)$ . Answer