jose wants to use a glass rod as an insulator. the rods diameter is 9 mm and kts resistivity is 1×10^9m. how long must be the rod to he offer a resistance of 9.1×10^10 ohms?
R=ρlA→l=RAρR=\rho \frac{l}{A}\to l=\frac{RA}{\rho}R=ρAl→l=ρRA
A=πd2/4=3.14⋅0.0092/4=6.36⋅10−5 (m2)A=\pi d^2/4=3.14\cdot0.009^2/4=6.36\cdot10^{-5}\ (m^2)A=πd2/4=3.14⋅0.0092/4=6.36⋅10−5 (m2)
l=RAρ=9.1⋅1010⋅6.36⋅10−51⋅109≈0.006 (m2)=6 (mm)l=\frac{RA}{\rho}=\frac{9.1\cdot10^{10}\cdot 6.36\cdot 10^{-5}}{1\cdot10^9}\approx0.006\ (m^2)=6\ (mm)l=ρRA=1⋅1099.1⋅1010⋅6.36⋅10−5≈0.006 (m2)=6 (mm) . Answer
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