Answer to Question #175034 in Physics for Sanithu Thenujaya

Question #175034

One end of a 50 cm length of wire is attached to a support. A load is attached to the free end of the wire, which extends by 2 mm.

Which of the following is the strain for the length of wire?

A 0.004

B 0.04

C 25

D 250


1
Expert's answer
2021-03-24T19:39:35-0400

By definition, the strain is:


ϵ=ΔLL\epsilon = \dfrac{\Delta L}{L}

where ΔL=2mm=0.2cm\Delta L = 2mm = 0.2cm is the extension, and L=50cmL = 50cm is the initial length of the wire. Thus, obtain:


ϵ=0.2cm50cm=0.004\epsilon = \dfrac{0.2cm}{50cm} = 0.004

Answer. 0.004.


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