Question #174899

A 0.5 kg pendulum bob is raised to 1.0 m above the floor, as shown in the image to the right. The bob is then released from rest. When the bob is 0.8 m above the floor, its speed is most nearly…

(A) 5 m/s

(B) 4 m/s

(C) 2 m/s

(D) 1 m/s




1
Expert's answer
2021-03-24T19:40:12-0400

mgH=mgh+mv2/2mgH=mgh+mv^2/2\to


v=2g(Hh)=29.81(10.8)=1.98 (m/s)2 (m/s)v=\sqrt{2g(H-h)}= \sqrt{2\cdot9.81\cdot (1-0.8)}=1.98\ (m/s)\approx2\ (m/s)


(C) 2 m/s(C)\ 2\ m/s . Answer

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

Sebastian Catanzaro
03.08.22, 02:24

Thank you guys so much keep doing what you guys are doing.

LATEST TUTORIALS
APPROVED BY CLIENTS