Question #174828

A steel spring has a spring constant of 2 × 102 Nm-1. Calculate the weight of an object which when attached to the unloaded spring produces an extension of 50 mm. The elastic limit is NOT exceeded


1
Expert's answer
2021-03-24T19:41:03-0400

F=kx=200⋅0.05=10 (N)F=kx=200\cdot0.05=10\ (N)


or


m=F/g=10/9.81=1.02 (kg)m=F/g=10/9.81=1.02\ (kg)


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