With what velocity must a 95 g softball be moving to equal the momentum of a 0.32 kg baseball moving at 12 m/s
p=mv=0.32⋅12=3.84 (kg⋅m/s)p=mv=0.32\cdot12=3.84\ (kg\cdot m/s)p=mv=0.32⋅12=3.84 (kg⋅m/s)
v0=p/m0=3.84/0.095=40.4 (m/s)v_0=p/m_0=3.84/0.095=40.4\ (m/s)v0=p/m0=3.84/0.095=40.4 (m/s) . Answer
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