How much power is required to make a 1400 kg car accelerate from 0 ms-1 to 20+your birth date ms-1 in 4.5 seconds?
Assume that your birth date 15.05.2005
W=KE=mv22=1400⋅(20+15)22=857500 (J)W=KE=\frac{mv^2}{2}=\frac{1400\cdot (20+15)^2}{2}=857500\ (J)W=KE=2mv2=21400⋅(20+15)2=857500 (J)
P=W/t=857500/4.5≈191 (kW)P=W/t=857500/4.5\approx191\ (kW)P=W/t=857500/4.5≈191 (kW) . Answer
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