A forward Horizontal force of 12N is used to pull a 240 N crate at a constant velocity across a horizontal floor. The coefficient of friction is?
"F=ma"
"a=0,\\ v=const"
"F-F_f=0\\to F_f=F\\to \\mu N=F\\to\\mu=F\/N"
"\\mu=\\frac{F}{N}=\\frac{F}{mg}=\\frac{12}{240}=0.05" . Answer
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