7. A sample constant 4.5 x 1018 atoms of a radioactive isotope . If it has a decay constant of 1.1 x10-12 s-1, what is the activity of the sample ?
A=λN=1.1⋅10−12⋅4.5⋅1018=4950000 (Bq)=4.95⋅106 (Bq)A=\lambda N=1.1\cdot10^{-12}\cdot4.5\cdot10^{18}=4950000\ (Bq)=4.95\cdot10^6\ (Bq)A=λN=1.1⋅10−12⋅4.5⋅1018=4950000 (Bq)=4.95⋅106 (Bq)
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