5. On the rod with a length of 70 cm that has a rotating shaft at the end O, the force F = 40N acts, the direction of which forms the angle 60⁰ with the rod. Find the moment of force acting on the rod.
"\\tau=Fl\\sin\\alpha=40\\cdot0.7\\cdot\\sin60\u00b0=24.25\\ (N\\cdot m)" . Answer
Comments
Leave a comment