The rod with negligible mass rests on points A and B. The body with mass 22kg hangs on the C end of the rod. Find the forces acting on points A and B, if AC = 50cm and BC = 10cm.
∑τA=0→(0.5−0.1)FB−0.5mg=0→0.4FB=0.5⋅22⋅9.8→\sum \tau^A=0\to(0.5-0.1)F_B-0.5mg=0\to0.4F_B=0.5\cdot22\cdot9.8\to∑τA=0→(0.5−0.1)FB−0.5mg=0→0.4FB=0.5⋅22⋅9.8→
FB=269.5 (N)F_B=269.5\ (N)FB=269.5 (N)
∑τB=0→−(0.5−0.1)FA−0.1mg=0→−0.4FA=0.1⋅22⋅9.8→\sum \tau^B=0\to-(0.5-0.1)F_A-0.1mg=0\to-0.4F_A=0.1\cdot22\cdot9.8\to∑τB=0→−(0.5−0.1)FA−0.1mg=0→−0.4FA=0.1⋅22⋅9.8→
FA=−53.9 (N)F_A=-53.9\ (N)FA=−53.9 (N)
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