A flywheel rotates at an angular velocity (omega) = 31.4 rad / s. The moment of inertia is 63.6 kg / m². Inhibitory forces act on it. Find the braking moment M, under the action of which the flywheel stops after 20 S.
"\\tau=I\\epsilon\\to\\tau=I\\frac{\\Delta\\omega}{\\Delta t}=63.6\\cdot\\frac{0-31.4}{20}=-99.85\\ (N\\cdot m)" . Answer
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