Answer to Question #174051 in Physics for Moussa

Question

The cylinder has a density of 21186 kg m³ and hight of 39.17 mm. Calculate the cross sectional area of the cylinder

Answer 1

Mass of the cylinder:

$$m=\rho V.$$

Its volume:

$$V=Ah,$$

where A - the cross-cectional area. Thus,

$$m=\rho Ah, \\\space\\ A=\frac{m}{\rho h}=\frac{m}{21186·0.03917}=\frac{m}{829.86}\text{ (m}^2).$$