A stone of weight 50N is completely immersed in a fluid. The weight of the stone shown on the spring balance is 48N. Calculate the volume of the stone
Given the density of fluid is 2100kg/m3
FG0−FG−FB=0→50−48=ρVg→F_{G0}-F_G-F_B=0\to50-48=\rho Vg\toFG0−FG−FB=0→50−48=ρVg→
V=2ρg=22100⋅9.8=9.7⋅10−5 (m3)=97 (cm3)V=\frac{2}{\rho g}=\frac{2}{2100\cdot9.8}=9.7\cdot10^{-5}\ (m^3)=97\ (cm^3)V=ρg2=2100⋅9.82=9.7⋅10−5 (m3)=97 (cm3) . Answer
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