Answer to Question #173791 in Physics for Isey

Question #173791

What will be the potential if atest charge id placed 2.08x10^-3 m away from the +5.02x10-13C source charge?

Expert's answer

The test potential will be

"V=\\frac{kq}{r}=\\frac{9\u00b710^9\u00b75.02\u00b710^{-13}}{2.08\u00b710^{-3}}=2.17\\text{ V}."

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