What wilk be the electric potentialif the source charge is +4.02x10^-13C and a test charge will be placed 4.55x10^-12m from it?
"\\phi=k\\frac{q}{r}=9\\cdot10^9\\cdot\\frac{4.02\\cdot10^{-13}}{4.55\\cdot10^{-12}}\\approx795\\ (MV)" . Answer
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