A car with a mass of 2500 kg and moving at 3 m/s northeast collides with a 3000 kg car moving northwest at 2.5 m/s . Find their final velocities. Assume a perfectly inelastic collision.
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p1x+p2x=px→px=2500⋅3⋅cos45°−3000⋅2.5⋅cos45°=0p_{1x}+p_{2x}=p_x\to p_x=2500\cdot3\cdot\cos45°-3000\cdot2.5\cdot\cos45°=0p1x+p2x=px→px=2500⋅3⋅cos45°−3000⋅2.5⋅cos45°=0
p1y+p2y=py→py=2500⋅3⋅sin45°+3000⋅2.5⋅sin45°=10607 (kg⋅m/s)p_{1y}+p_{2y}=p_y\to p_y=2500\cdot3\cdot\sin45°+3000\cdot2.5\cdot\sin45°=10607\ (kg\cdot m/s)p1y+p2y=py→py=2500⋅3⋅sin45°+3000⋅2.5⋅sin45°=10607 (kg⋅m/s)
p=px2+py2=02+106072=10607 (kg⋅m/s)p=\sqrt{p_x^2+p_y^2}=\sqrt{0^2+10607^2}=10607\ (kg\cdot m/s)p=px2+py2=02+106072=10607 (kg⋅m/s)
p=(m1+m2)v→v=p/(m1+m2)=10607/(2500+3000)=1.93 (m/s)p=(m_1+m_2)v\to v=p/(m_1+m_2)=10607/(2500+3000)=1.93\ (m/s)p=(m1+m2)v→v=p/(m1+m2)=10607/(2500+3000)=1.93 (m/s) . Answer
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