Answer to Question #173429 in Physics for Ashley Gonzales

Question

if a box has 2.0x10^2J of work done to it, is moved with 55N. what is the distance it moved?

Answer 1

By the definition of the work done, we have:

$$W=Fd,$$ $$d=\dfrac{W}{F}=\dfrac{2.0\cdot10^2\ J}{55\ N}=3.64\ m.$$