Three masses are located in the vertices of an equilateral triangle. Calculate the magnitude and direction of the gravitational force on the mass m₁. Given: m₁ = 38 kg, m₂ = 340 kg, m₃ = 340 kg, r = 38 m. G = 6.674×10–11 N·m²/kg².
Let "r" is the side of the triangle. So, we have
"F_2=F_3=G\\frac{m_1m_2}{r^2}=6.674\\cdot10^{-11}\\cdot \\frac{38\\cdot 340}{38^2}\\approx5.97\\cdot10^{-10}\\ (N)"
"F_{total}=2\\cdot5.97\\cdot10^{-10}\\cdot\\cos30\u00b0=1.03\\cdot10^{-9}\\ (N)" . Answer
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