Answer to Question #173268 in Physics for Denisse Bisuña

Question #173268

a 0.05 kg tennis ball approaches a rocket at 25 m/s. if it is in contact with the racket's strings for 0.005 s, then rebounds at 25 m/s, what is the average contact force between the ball and the racket? Ignore the air resistance.


1
Expert's answer
2021-03-23T08:14:22-0400
FavgΔt=mΔv,F_{avg}\Delta t=m\Delta v,FavgΔt=m(vfvi),F_{avg}\Delta t=m(v_f-v_i),Favg=m(vfvi)Δt,F_{avg}=\dfrac{m(v_f-v_i)}{\Delta t},Favg=0.05 kg(25 ms25 ms)0.005 s=500 N.F_{avg}=\dfrac{0.05\ kg\cdot(-25\ \dfrac{m}{s}-25\ \dfrac{m}{s})}{0.005\ s}=-500\ N.

The sign minus means that the average contact force between the ball and the racket directed away from the racket.


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