Question

A parallel-plate capacitor with metal plates of area 1.00 m² are separated by 1.00 mm. What is the charge stored when connected to a potential difference of 3.00 x 10³ V.

Answer 1

$C=\frac{\epsilon_0A}{l}=\frac{8.85\cdot10^{-12}\cdot1}{0.001}=8.85\cdot10^{-9}\ (F)$

$q=CV=8.85\cdot10^{-9}\cdot3000=26.55\cdot10^{-6}\ (C)=26.55\ (\mu C)$ . Answer