The charge stored on each plate of a capacitor is 120 uC when it is connected to a source with a potential difference of 6.0 V. What is the potential difference across the capacitor if the charge on each plate is 64uC?
C=q/V=120⋅10−6/6=20⋅10−6 (F)C=q/V=120\cdot10^{-6}/6=20\cdot10^{-6}\ (F)C=q/V=120⋅10−6/6=20⋅10−6 (F)
V=q/C=64⋅10−6/20⋅10−6=3.2 (V)V=q/C=64\cdot10^{-6}/20\cdot10^{-6}=3.2\ (V)V=q/C=64⋅10−6/20⋅10−6=3.2 (V) . Answer
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