Question #173177

Consider the charges ๐‘ž1=2.5 ๐œ‡๐ถ and ๐‘ž2=-2 ๐œ‡๐ถ located at (๐‘ฅ1,๐‘ฆ1,๐‘ง1)=(1,โˆ’2,4) ๐‘š and (๐‘ฅ2,๐‘ฆ2,๐‘ง2)=(2,-1, 3) ๐‘š, respectively. Assume the charges are in the air.

a.) Determine the force exerted by charge ๐‘ž2 on ๐‘ž1

b.) Calculate the magnitude of the force on part a.

c.) Find the electric field at (๐‘ฅ1,๐‘ฆ1,๐‘ง1) induced by charge ๐‘ž2

d.) Determine the force exerted on charge ๐‘ždue to the electric field of charge ๐‘ž2.


1
Expert's answer
2021-03-23T08:07:51-0400

a) Determine the force exerted by charge ๐‘ž2 on ๐‘ž1:


F=kq1q2r2F=k\frac{q_1q_2}{r^2}


b) Calculate the magnitude of the force on part a.


F=9โ‹…1092.5โ‹…10โˆ’6โ‹…2โ‹…10โˆ’6(2โˆ’1)2+(โˆ’1โˆ’(โˆ’2))2+(3โˆ’4)2=0.015 N.F=9ยท10^9\frac{2.5ยท10^{-6}ยท2ยท10^{-6}}{(2-1)^2+(-1-(-2))^2+(3-4)^2}=0.015\text{ N}.


c) Find the electric field at (๐‘ฅ1,๐‘ฆ1,๐‘ง1) induced by charge ๐‘ž2

E=Fq1=kq1r2=7500 V/m.E=\frac{F}{q_1}=k\frac{q_1}{r^2}=7500\text{ V/m}.


d) Determine the force exerted on charge ๐‘ždue to the electric field of charge ๐‘ž2.


F=Eq1=kq1q2r2=0.015 N.F=Eq_1=k\frac{q_1q_2}{r^2}=0.015\text{ N}.

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