Answer to Question #173177 in Physics for Shai

Question #173177

Consider the charges π‘ž1=2.5 πœ‡πΆ and π‘ž2=-2 πœ‡πΆ located at (π‘₯1,𝑦1,𝑧1)=(1,βˆ’2,4) π‘š and (π‘₯2,𝑦2,𝑧2)=(2,-1, 3) π‘š, respectively. Assume the charges are in the air.

a.) Determine the force exerted by charge π‘ž2 on π‘ž1

b.) Calculate the magnitude of the force on part a.

c.) Find the electric field at (π‘₯1,𝑦1,𝑧1) induced by charge π‘ž2

d.) Determine the force exerted on charge π‘ždue to the electric field of charge π‘ž2.


1
Expert's answer
2021-03-23T08:07:51-0400

a) Determine the force exerted by charge π‘ž2 on π‘ž1:


F=kq1q2r2F=k\frac{q_1q_2}{r^2}


b) Calculate the magnitude of the force on part a.


F=9β‹…1092.5β‹…10βˆ’6β‹…2β‹…10βˆ’6(2βˆ’1)2+(βˆ’1βˆ’(βˆ’2))2+(3βˆ’4)2=0.015 N.F=9Β·10^9\frac{2.5Β·10^{-6}Β·2Β·10^{-6}}{(2-1)^2+(-1-(-2))^2+(3-4)^2}=0.015\text{ N}.


c) Find the electric field at (π‘₯1,𝑦1,𝑧1) induced by charge π‘ž2

E=Fq1=kq1r2=7500 V/m.E=\frac{F}{q_1}=k\frac{q_1}{r^2}=7500\text{ V/m}.


d) Determine the force exerted on charge π‘ždue to the electric field of charge π‘ž2.


F=Eq1=kq1q2r2=0.015 N.F=Eq_1=k\frac{q_1q_2}{r^2}=0.015\text{ N}.

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