Question

A model car is moving around a circular track of radius 3.0 m at a speed of 1.5 m s⁻¹ as shown in the figure. It takes the car 12.6 s to complete one full lap.

What is the magnitude of the average velocity of the car (a) between point A and point B? (in m s⁻¹ to 2 s.f)

NOTE: The motion of the car is NOT an example of constant acceleration.

Answer 1

If points A and B at the opposite sides of the diameter of the circle, the velocity vector will rotate 180°. Since the average velocity is a vector sum, then the average velocity will be

$$-v+v=0.00\text{ m/s}.$$