Question #173031

A copper 20cm on a side is completely submerged underwater. Calculate the buoyant force acting on the cube?

a.58.7 N b. 75.8 N c. 78.5 N d. 87.5 N




1
Expert's answer
2021-04-26T17:00:18-0400

The volume of the cube is V=l3=(0.2m)3=0.008m3V = l^3 = (0.2 m)^3 = 0.008 m^3.

Buoyant force, acting on it is F=ρgVF = \rho g V, where ρ\rho is the density of water, gg is gravitational acceleration and VV is the submerged volume.

Hence, F=1000kgm39.81ms20.008m378.5NF = 1000 \frac{kg}{m^3} \cdot 9.81 \frac{m}{s^2} \cdot 0.008 m^3 \approx 78.5 N, so the answer is c).


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS