Answer to Question #172719 in Physics for Mathew Domach

Question #172719

a 78.2kg person is standing on a scale in a elevator. if the elevator is accelerating downwards at 0.307 m/s square what will be on the scale be ( in kilograms

Expert's answer

"m'=\\frac{W'}{g}\\\\m'=\\frac{m(g-a)}{g}\\\\m'=\\frac{78.2(9.8-0.307)}{9.8}=75.75\\ kg"

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