Answer to Question #172606 in Physics for Jeet

Question #172606

Find the force between two point charges 5uc and 10uc separated by a distance of 0.2m in air.

Expert's answer

"F=\\dfrac{kq_1q_2}{r^2},""F=\\dfrac{9\\cdot10^9\\ \\dfrac{Nm^2}{C^2}\\cdot5\\cdot10^{-6}\\ C\\cdot10\\cdot10^{-6}\\ C}{(0.2\\ m)^2}=11.25\\ N."

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Comments

Catherine

19.09.23, 00:52

Thanks a lot for answering my question.

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