Answer to Question #172606 in Physics for Jeet

Question

Find the force between two point charges 5uc and 10uc separated by a distance of 0.2m in air.

Answer 1

$$F=\dfrac{kq_1q_2}{r^2},$$ $$F=\dfrac{9\cdot10^9\ \dfrac{Nm^2}{C^2}\cdot5\cdot10^{-6}\ C\cdot10\cdot10^{-6}\ C}{(0.2\ m)^2}=11.25\ N.$$