Question #172491

A wheel 1.0 m in radius rotates with an angular acceleration of 4.0rad/s2


1) If the wheel’s initial angular velocity is 2.0 rad/s, its angular velocity after 10 s is


2)The angle in radians it rotates in the 10-s interval is


3)The tangential speed of the point on the rim of the wheel at the end of the 10-s interval is


4)The tangential acceleration of the point on the rim of the wheel at the end of the 10-s interval is


1
Expert's answer
2021-03-17T16:52:49-0400

1) If the wheel’s initial angular velocity is 2.0 rad/s, its angular velocity after 10 s is


ωf=ωi+αt=2+410=42 rad/s.\omega_f=\omega_i+\alpha t=2+4·10=42\text{ rad/s}.

2) The angle in radians it rotates in the 10-s interval is


ϕ=ωit+αt22=220 rad.\phi=\omega_it+\frac{\alpha t^2}{2}=220\text{ rad}.

3) The tangential speed of the point on the rim of the wheel at the end of the 10-s interval is


v=ωfR=421=42 m/s.v=\omega_fR=42·1=42\text{ m/s}.

4) The tangential acceleration of the point on the rim of the wheel at the end of the 10-s interval is


a=αR=41=4 m/s2.a=\alpha R=4·1=4\text{ m/s}^2.

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